博客
关于我
玲珑学院-ACM比赛1014 - Absolute Defeat
阅读量:436 次
发布时间:2019-03-06

本文共 1423 字,大约阅读时间需要 4 分钟。

1014 - Absolute Defeat

Time Limit:2s Memory Limit:64MByte

Submissions:257Solved:73

DESCRIPTION
Eric has an array of integers
a1,a2,...,ana1,a2,...,an. Every time, he can choose a contiguous subsequence of length
kk and increase every integer in the contiguous subsequence by
11.He wants the minimum value of the array is at least
mm. Help him find the minimum number of operations needed.
INPUT
There are multiple test cases. The first line of input contains an integer
TT, indicating the number of test cases. For each test case:The first line contains three integers
nn,
mm and
kk
(1n105,1kn,1m104)(1≤n≤105,1≤k≤n,1≤m≤104).The second line contains
nn integers
a1,a2,...,ana1,a2,...,an
(1ai104)(1≤ai≤104).
OUTPUT
For each test case, output an integer denoting the minimum number of operations needed.
SAMPLE INPUT
32 2 21 15 1 41 2 3 4 54 10 31 2 3 4
SAMPLE OUTPUT

1015

源代码:

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
using namespace std;typedef long long ll;int ans[200005];int main(){ int t; int n,m,k; int temp; ll sum; scanf("%d",&t); while(t--) { scanf("%d%d%d",&n,&m,&k); sum = 0; memset(ans,0x3f3f3f3f,sizeof(ans)); for(int i = 0; i < n; i++) scanf("%d",&ans[i]); for(int i = 0; i < n; i++) { if(ans[i]

转载地址:http://txjyz.baihongyu.com/

你可能感兴趣的文章
MySQL-8.0.16 的安装与配置
查看>>
MySQL-Buffer的应用
查看>>
mysql-cluster 安装篇(1)---简介
查看>>
mysql-connector-java.jar乱码,最新版mysql-connector-java-8.0.15.jar,如何愉快的进行JDBC操作...
查看>>
mysql-connector-java各种版本下载地址
查看>>
mysql-EXPLAIN
查看>>
MySQL-Explain的详解
查看>>
mysql-group_concat
查看>>
MySQL-redo日志
查看>>
MySQL-【1】配置
查看>>
MySQL-【4】基本操作
查看>>
Mysql-丢失更新
查看>>
Mysql-事务阻塞
查看>>
Mysql-存储引擎
查看>>
mysql-开启慢查询&所有操作记录日志
查看>>
MySQL-数据目录
查看>>
MySQL-数据页的结构
查看>>
MySQL-架构篇
查看>>
MySQL-索引的分类(聚簇索引、二级索引、联合索引)
查看>>
Mysql-触发器及创建触发器失败原因
查看>>